Выполните сложение.
а) $3\frac{3}{5} + \frac{1}{5} = 3 + \frac{3}{5} + \frac{1}{5} = 3 + (\frac{3}{5} + \frac{1}{5}) = 3\frac{4}{5}$
б) $4\frac{3}{7} + 2\frac{4}{7} = 6\frac{7}{7} = 6 + 1 = 7$
в) $3\frac{5}{6} + \frac{1}{6} =$
г) $15\frac{3}{8} + 4\frac{2}{8} =$
д) $\frac{7}{11} + 3\frac{2}{11} =$
е) $9\frac{3}{10} + 4\frac{1}{10} =$
ж) $17\frac{5}{12} + 1\frac{7}{12} =$
з) $\frac{1}{9} + 9\frac{8}{9} =$

$3\frac{3}{5} + \frac{1}{5} = 3 + \frac{3}{5} + \frac{1}{5} = 3 + (\frac{3}{5} + \frac{1}{5}) = 3\frac{4}{5}$
$4\frac{3}{7} + 2\frac{4}{7} = 6\frac{7}{7} = 6 + 1 = 7$
$3\frac{5}{6} + \frac{1}{6} = 3 + \frac{5}{6} + \frac{1}{6} = 3 + (\frac{5}{6} + \frac{1}{6}) = 3\frac{6}{6} = 4$
$15\frac{3}{8} + 4\frac{2}{8} = (15 + 4) + (\frac{3}{8} + \frac{2}{8}) = 19\frac{5}{8}$
$\frac{7}{11} + 3\frac{2}{11} = 3 + \frac{7}{11} + \frac{2}{11} = 3 + (\frac{7}{11} + \frac{2}{11}) = 3\frac{9}{11}$
$9\frac{3}{10} + 4\frac{1}{10} = (9 + 4) + (\frac{3}{10} + \frac{1}{10}) = 13\frac{4}{10}$
$17\frac{5}{12} + 1\frac{7}{12} = (17 + 1) + (\frac{5}{12} + \frac{7}{12}) = 18\frac{12}{12} = 19$
$\frac{1}{9} + 9\frac{8}{9} = 9 + \frac{1}{9} + \frac{8}{9} = 9 + (\frac{1}{9} + \frac{8}{9}) = 9\frac{9}{9} = 10$