Найдите $(\frac{2}{3})^k$, если:
а) k = 3;
б) k = 0;
в) k = 1;
г) k = 5.
k = 3
$(\frac{2}{3})^k = (\frac{2}{3})^3 = \frac{8}{27}$
k = 0
$(\frac{2}{3})^k = (\frac{2}{3})^0 = 1$
k = 1
$(\frac{2}{3})^k = (\frac{2}{3})^1 = \frac{2}{3}$
k = 5
$(\frac{2}{3})^k = (\frac{2}{3})^5 = \frac{32}{243}$