Решите уравнение: $\frac{x^2 * x^3 * (x^3)^3}{x^5 * (x^2)^4} = 49$.
$\frac{x^2 * x^3 * (x^3)^3}{x^5 * (x^2)^4} = 49$ $\frac{x^5 * x^9}{x^5 * x^8} = 49$ $\frac{x^{14}}{x^{13}} = 49$ x = 49
