Упростите выражение:
а) $\frac{1 + \frac{a - x}{x}}{ax}$;
б) $\frac{\frac{a^2 - b^2}{a^2} - 1}{2a^2b^2}$.
$\frac{1 + \frac{a - x}{x}}{ax} = (1 + \frac{a - x}{x}) * \frac{1}{ax} = \frac{x + a - x}{x} * \frac{1}{ax} = \frac{a}{x} * \frac{1}{ax} = \frac{1}{x^2}$
$\frac{\frac{a^2 - b^2}{a^2} - 1}{2a^2b^2} = (\frac{a^2 - b^2}{a^2} - 1) * \frac{1}{2a^2b^2} = \frac{a^2 - b^2 - a^2}{a^2} * \frac{1}{2a^2b^2} = -\frac{b}{a^2} * \frac{1}{2a^2b^2} = -\frac{1}{2a^4}$