Решите уравнение:
1) $\frac{5x - 4}{2} = \frac{16x + 1}{7}$;
2) $\frac{4y + 33}{3} = \frac{17 + y}{2}$.
$\frac{5x - 4}{2} = \frac{16x + 1}{7}$
7(5x − 4) = 2(16x + 1)
35x − 28 = 32x + 2
35x − 32x = 2 + 28
3x = 30
x = 30 : 3 = 3
$\frac{4y + 33}{3} = \frac{17 + y}{2}$
3(17 + y) = 2(4y + 33)
51 + 3y = 8y + 66
3y − 8y = 66 − 51
−5y = 15
y = 15 : −5
y = −3